What is the domain of sqrt((x^2)/(x^2-1)) ?

The domain of sqrt((x^2)/(x^2-1)) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of sqrt((x^2)/(x^2-1))

domain

\frac{x ^{2}}{x ^{2} - 1}

x < - 1 or x = 0 or x > 1

Interval Notation

(- \infty, - 1) \cup x = 0 \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x < - 1 or x = 0 or x > 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x = 0 or x > 1

f (x) = \frac{2 x ^{2} - 7 x + 2}{x - 4}

f (x) = x^{\frac{6}{5}} - 12 x^{\frac{1}{5}}

- 3 x - 2 y = 6

x^{2} + y - 25 = 0

f (x) = \frac{2 x}{x ^{2} + 81}

What is the domain of sqrt((x^2)/(x^2-1)) ?
The domain of sqrt((x^2)/(x^2-1)) is x<-1\lor x=0\lor x>1