What is the domain of f(x)= 1/(3x-x^2) ?

The domain of f(x)= 1/(3x-x^2) is x 3

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domain of f(x)= 1/(3x-x^2)

domain

f (x) = \frac{1}{3 x - x ^{2}}

x < 0 or 0 < x < 3 or x > 3

Interval Notation

(- \infty, 0) \cup (0, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = 3

The function domain

x < 0 or 0 < x < 3 or x > 3

\frac{x ^{2}}{x ^{2} - 16}

f (x) = \frac{2}{1 - x ^{2}}

f (x) = ln (3 x + 2)

(14, - 2), (7, - 8)

f (x) = (x - 9)^{3}

What is the domain of f(x)= 1/(3x-x^2) ?
The domain of f(x)= 1/(3x-x^2) is x<0\lor 0<x<3\lor x>3