extreme xsqrt(2-x)

Lösung

extrempunkte

x 2 - x

Maximum (\frac{4}{3}, \frac{4 2}{3 3}), Minimum (2, 0)

Schritte zur Lösung

f^{'} (x) = \frac{- 3 x + 4}{2 2 - x}

Intervalle finden:

Ansteigend

: - \infty < x < \frac{4}{3},

Absteigend

: \frac{4}{3} < x < 2

Stecke

x = \frac{4}{3}

x 2 - x : \frac{4 2}{3 3}

Maximum (\frac{4}{3}, \frac{4 2}{3 3})

Stecke

x = 2

x 2 - x : 0

Minimum (2, 0)

Maximum (\frac{4}{3}, \frac{4 2}{3 3}), Minimum (2, 0)

e x t re m e f (x) = x^{3} + 2 x^{2} - x - 2

e x t re m e f (x, y) = arcsec (x^{2} - ∣ y ∣)

e x t re m e f (x) = 2 x^{2} - 4 x y + 3 y^{2} - 8 x + 8 y - 1 = 0

e x t re m e f (x) = x^{3} + 3 y^{3} + 3 x^{2} + 3 y^{2} + 24

e x t re m e f (x) = \frac{2 x ^{3}}{3} + \frac{3 x ^{2}}{2} - 2 x