What is the domain of f(x)=(x^2-1)/(3x+9) ?

The domain of f(x)=(x^2-1)/(3x+9) is x -3

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domain of f(x)=(x^2-1)/(3x+9)

domain

f (x) = \frac{x ^{2} - 1}{3 x + 9}

x < - 3 or x > - 3

Interval Notation

(- \infty, - 3) \cup (- 3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 3

The function domain

x < - 3 or x > - 3

y = \frac{4 x ^{2} + 1}{2 x}

\frac{x ^{2} - 5}{7 x ^{2}}

f (x) = \frac{x ^{2} - 1}{x ^{2} + 2 x - 3}

f (x) = \frac{3}{x ^{2} + 6 x - 4}

What is the domain of f(x)=(x^2-1)/(3x+9) ?
The domain of f(x)=(x^2-1)/(3x+9) is x<-3\lor x>-3