What is the domain of x/(\sqrt[4]{64-x^2)} ?

The domain of x/(\sqrt[4]{64-x^2)} is -8<x<8

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domain of x/(\sqrt[4]{64-x^2)}

domain

- 8 < x < 8

Interval Notation

(- 8, 8)

Solution steps

Find non-negative values for radicals:

- 8 \leq x \leq 8

Find undefined (singularity) points:

x = 8, x = - 8

Combine real regions and undefined points for final function domain

- 8 < x < 8

f (x) = \frac{3}{x - 4}

y = - \frac{5}{6} x + \frac{1}{6}, (5, - 4)

f (x) = 3 x^{2} + x + 2

x + 3 - 2

f (x) = x 50 - x^{2}

What is the domain of x/(\sqrt[4]{64-x^2)} ?
The domain of x/(\sqrt[4]{64-x^2)} is -8<x<8