What is the domain of (x-1)^2,x>= 1 ?

The domain of (x-1)^2,x>= 1 is x>= 1

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domain of (x-1)^2,x>= 1

domain

(x - 1)^{2}, x \geq 1

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Set the domain to the given interval

x \geq 1

The function has no undefined points nor domain constraints. Therefore, the domain is

x \geq 1

f (x) = \frac{1 + x}{x ^{2} - 1}

3 x = 9

f (x) = \frac{1}{( x + 4 )}

f (x) = \frac{x ^{2} + 6 x - 8}{x - 8}

f (x) = (\frac{2}{x}) \cdot (\frac{x}{x + 2})