What is the domain of g(x)=\sqrt[4]{x^2-6x} ?

The domain of g(x)=\sqrt[4]{x^2-6x} is x = 6

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domain of g(x)=\sqrt[4]{x^2-6x}

domain

x \leq 0 or x \geq 6

Interval Notation

(- \infty, 0] \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 6

The function domain

x \leq 0 or x \geq 6

\frac{1}{x} + 2

f (x) = 35 - 5 x

f (x) = \frac{2 - x ^{2}}{x ^{2} - 9}

f (x) = 8 - 3 x

x^{3} - 2 x^{2} - 15 x + 10

What is the domain of g(x)=\sqrt[4]{x^2-6x} ?
The domain of g(x)=\sqrt[4]{x^2-6x} is x<= 0\lor x>= 6