What is the f(x)=sqrt(x^2-4) ?

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f(x)=sqrt(x^2-4)

f (x) = x^{2} - 4

Domain : x \leq - 2 or x \geq 2

Range : f (x) \geq 0

X Intercepts : (2, 0), (- 2, 0)

Asymptotes : Slant y = x, y = - x

Extreme Points : Minimum (- 2, 0), Minimum (2, 0)

Interval Notation

Domain : (- \infty, - 2] \cup [2, \infty)

Range : [0, \infty)

Solution steps

Domain of

x^{2} - 4 : x \leq - 2 or x \geq 2

Range of

x^{2} - 4 : f (x) \geq 0

Axis interception points of

x^{2} - 4 :

X Intercepts

: (2, 0), (- 2, 0)

Asymptotes of

x^{2} - 4 :

Slant

: y = x, y = - x

Extreme Points of

x^{2} - 4 :

Minimum

(- 2, 0),

Minimum

(2, 0)

f (x) = \frac{1}{x ^{2} - x - 6}

f (x) = x e^{- 4 π x}

f (x) = \frac{3 x}{2 x + 1}

f (x) = \frac{( x + 19 )}{x - 17}

f (x) = \frac{2}{( x - 1 ) ^{3}}