What is the domain of f(x)=sqrt(x-9)+sqrt(x+14) ?

The domain of f(x)=sqrt(x-9)+sqrt(x+14) is x>= 9

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domain of f(x)=sqrt(x-9)+sqrt(x+14)

domain

f (x) = x - 9 + x + 14

x \geq 9

Interval Notation

[9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 9

The function domain

x \geq 9

f (x) = - 3 x + 4

f (x) = x^{2} + 9, x \geq 0

f (x) = x + x + 5

f (x) = ln (9 x^{2} + 1)

y = \frac{( x - 9 )}{( x - 2 )}

What is the domain of f(x)=sqrt(x-9)+sqrt(x+14) ?
The domain of f(x)=sqrt(x-9)+sqrt(x+14) is x>= 9