What is the range of y=3-2sin(3x-pi) ?

The range of y=3-2sin(3x-pi) is 1<= f(x)<= 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of y=3-2sin(3x-pi)

range

y = 3 - 2 sin (3 x - π)

1 \leq f (x) \leq 5

Interval Notation

[1, 5]

Solution steps

The range of the basic

sin

function is

- 1 \leq sin (3 x - π) \leq 1

- 1 \leq sin (3 x - π) \leq 1

Multiply the edges of the range by:

- 2

- 2 \leq - 2 sin (3 x - π) \leq 2

Add to the edges of the range:

3

1 \leq - 2 sin (3 x - π) + 3 \leq 5

Therefore the range is

1 \leq f (x) \leq 5

f (x) = \frac{4 x + 9}{5 x - 6}

f (x) = \frac{x + 4}{x ^{2} - 5 x + 6}

x - 3^{2}

f (x) = sin (cot (x))

y = 2 x + 22

What is the range of y=3-2sin(3x-pi) ?
The range of y=3-2sin(3x-pi) is 1<= f(x)<= 5