What is the domain of f(x)=sqrt(3-2x-x^2) ?

The domain of f(x)=sqrt(3-2x-x^2) is -3<= x<= 1

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domain of f(x)=sqrt(3-2x-x^2)

domain

f (x) = 3 - 2 x - x^{2}

- 3 \leq x \leq 1

Interval Notation

[- 3, 1]

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 1

The function domain

- 3 \leq x \leq 1

f (x) = - x^{3} + 7 x^{2} - 12 x

\frac{1}{x ^{2} - x}

f (x) = \frac{1}{( x - 3 ) ( x - 5 )}

f (x) = 3 x - 15

f (x) = 6 e^{x - 4}

What is the domain of f(x)=sqrt(3-2x-x^2) ?
The domain of f(x)=sqrt(3-2x-x^2) is -3<= x<= 1