What is the domain of f(x)= 1/(x^2-x-56) ?

The domain of f(x)= 1/(x^2-x-56) is x 8

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domain of f(x)= 1/(x^2-x-56)

domain

f (x) = \frac{1}{x ^{2} - x - 56}

x < - 7 or - 7 < x < 8 or x > 8

Interval Notation

(- \infty, - 7) \cup (- 7, 8) \cup (8, \infty)

Solution steps

Find undefined (singularity) points:

x = 8, x = - 7

The function domain

x < - 7 or - 7 < x < 8 or x > 8

f (x) = \frac{x}{1 + x ^{2}}

f (x) = (3 - 2 x)^{2} - 1

ln (x - 5)

x^{2} y^{2} + x y = 1

tan (3 x)

What is the domain of f(x)= 1/(x^2-x-56) ?
The domain of f(x)= 1/(x^2-x-56) is x<-7\lor-7<x<8\lor x>8