What is the domain of f(x)=\sqrt[3]{8-x^2} ?

The domain of f(x)=\sqrt[3]{8-x^2} is -infinity <x<infinity

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domain of f(x)=\sqrt[3]{8-x^2}

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

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f (x) = \frac{x ^{6}}{x ^{4} + 5}

4 x^{3} - 33 x^{2} + 84 x - 60

f (x) = - 4 x + 12

6 x^{2} sin (x) tan (x)

What is the domain of f(x)=\sqrt[3]{8-x^2} ?
The domain of f(x)=\sqrt[3]{8-x^2} is -infinity <x<infinity