What is the domain of f(x)= 1/(x^2+4x+3) ?

The domain of f(x)= 1/(x^2+4x+3) is x -1

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domain of f(x)= 1/(x^2+4x+3)

domain

f (x) = \frac{1}{x ^{2} + 4 x + 3}

x < - 3 or - 3 < x < - 1 or x > - 1

Interval Notation

(- \infty, - 3) \cup (- 3, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 3

The function domain

x < - 3 or - 3 < x < - 1 or x > - 1

e^{\frac{1}{x}}

f (x) = 1 - 2 x^{2}

y = sec (x)

y = \frac{1}{2} x - 3

x^{2} + 8 x + 14

What is the domain of f(x)= 1/(x^2+4x+3) ?
The domain of f(x)= 1/(x^2+4x+3) is x<-3\lor-3<x<-1\lor x>-1