What is the range of f(x)= 3/(sqrt(2x-4)) ?

The range of f(x)= 3/(sqrt(2x-4)) is f(x)>0

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range of f(x)= 3/(sqrt(2x-4))

range

f (x) = \frac{3}{2 x - 4}

f (x) > 0

Interval Notation

(0, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{3}{2 x - 4} : x > 2

Extreme Points of

\frac{3}{2 x - 4} :

None

Find the range for the interval

2 < x < \infty : 0 < f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) > 0

(x - 7)^{2} - 8

f (x) = x

f (x) = 2 x^{3} - 24 x - 2

f (x) = \frac{x + 5}{x ^{3} - x ^{2} - 4 x + 4}

3 x^{2} + x - 5

What is the range of f(x)= 3/(sqrt(2x-4)) ?
The range of f(x)= 3/(sqrt(2x-4)) is f(x)>0