What is the domain of f(x)=sqrt((9-x^2)(x+1)) ?

The domain of f(x)=sqrt((9-x^2)(x+1)) is x<=-3\lor-1<= x<= 3

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domain of f(x)=sqrt((9-x^2)(x+1))

domain

f (x) = (9 - x^{2}) (x + 1)

x \leq - 3 or - 1 \leq x \leq 3

Interval Notation

(- \infty, - 3] \cup [- 1, 3]

Solution steps

Find non-negative values for radicals:

x \leq - 3 or - 1 \leq x \leq 3

The function domain

x \leq - 3 or - 1 \leq x \leq 3

(- 8, - 3), (2, 3)

f (x) = \frac{14}{1 + 3 ^{- x}}

f (x) = \frac{1}{3} x + 7

\frac{1}{x + 6} + 5

- 4 x - 5 y = 7, (- 4, - 3)

What is the domain of f(x)=sqrt((9-x^2)(x+1)) ?
The domain of f(x)=sqrt((9-x^2)(x+1)) is x<=-3\lor-1<= x<= 3