What is the domain of f(x)=(sqrt(x))/(x-5) ?

The domain of f(x)=(sqrt(x))/(x-5) is 0 5

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domain of f(x)=(sqrt(x))/(x-5)

domain

f (x) = \frac{x}{x - 5}

0 \leq x < 5 or x > 5

Interval Notation

[0, 5) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 5

Combine real regions and undefined points for final function domain

0 \leq x < 5 or x > 5

f (x) = \frac{3 x}{x ^{2} + 5}

- 5 x^{2} + 118 x + 7

\frac{x}{x - 7}

\frac{2 x ^{3} + x ^{2} - 8 x - 4}{x ^{2} - 3 x + 2}

(1.7, 6.8), (- 9.2, - 12.1)

What is the domain of f(x)=(sqrt(x))/(x-5) ?
The domain of f(x)=(sqrt(x))/(x-5) is 0<= x<5\lor x>5