What is the domain of f(x)=sqrt(-32-20x-3x^2) ?

The domain of f(x)=sqrt(-32-20x-3x^2) is -4<= x<=-8/3

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domain of f(x)=sqrt(-32-20x-3x^2)

domain

f (x) = - 32 - 20 x - 3 x^{2}

- 4 \leq x \leq - \frac{8}{3}

Interval Notation

[- 4, - \frac{8}{3}]

Solution steps

Find non-negative values for radicals:

- 4 \leq x \leq - \frac{8}{3}

The function domain

- 4 \leq x \leq - \frac{8}{3}

f (x) = \frac{x ^{2} + x - 6}{x ^{2} + 6 x + 9}

f (x) = 2 x

y = 3 x^{2} + 12

f (x) = \frac{x - 3}{2 x + 1}

What is the domain of f(x)=sqrt(-32-20x-3x^2) ?
The domain of f(x)=sqrt(-32-20x-3x^2) is -4<= x<=-8/3