What is the range of y=2sin(x) ?

The range of y=2sin(x) is -2<= f(x)<= 2

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range of y=2sin(x)

range

y = 2 sin (x)

- 2 \leq f (x) \leq 2

Interval Notation

[- 2, 2]

Solution steps

The range of the basic

sin

function is

- 1 \leq sin (x) \leq 1

- 1 \leq sin (x) \leq 1

Multiply the edges of the range by:

2

- 2 \leq 2 sin (x) \leq 2

Therefore the range is

- 2 \leq f (x) \leq 2

(- 10, - 9), (0, 1)

f (x) = x^{2} - 6, x \geq 0

(0.6) (0)

(2, - 2), (- 1, 4)

f (x) = \frac{( x - 2 )}{( 4 x + 6 )}