What is the domain of f(x)=-sqrt(x^2-9) ?

The domain of f(x)=-sqrt(x^2-9) is x = 3

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domain of f(x)=-sqrt(x^2-9)

domain

f (x) = - x^{2} - 9

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

The function domain

x \leq - 3 or x \geq 3

x + 2

f (x) = 2 x^{\frac{1}{5}} - 4

x + x

f (x) = 6 x^{5} + 2

f (x) = \frac{x}{x - 3}

What is the domain of f(x)=-sqrt(x^2-9) ?
The domain of f(x)=-sqrt(x^2-9) is x<=-3\lor x>= 3