What is the domain of f(x)=(sqrt(x-1))/(x^2-4) ?

The domain of f(x)=(sqrt(x-1))/(x^2-4) is 1 2

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domain of f(x)=(sqrt(x-1))/(x^2-4)

domain

f (x) = \frac{x - 1}{x ^{2} - 4}

1 \leq x < 2 or x > 2

Interval Notation

[1, 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

Find undefined (singularity) points:

x = 2, x = - 2

Combine real regions and undefined points for final function domain

1 \leq x < 2 or x > 2

- 0.2 t^{2} + 2.4 t + 98.3

lo g_{b} (x)

7 x - 4 y = 28

(x + 6)^{2}

f (x) = 2 x^{3} + 3 x^{2} - 2

What is the domain of f(x)=(sqrt(x-1))/(x^2-4) ?
The domain of f(x)=(sqrt(x-1))/(x^2-4) is 1<= x<2\lor x>2