What is the domain of f(x)=sqrt(x^2+3x-4) ?

The domain of f(x)=sqrt(x^2+3x-4) is x = 1

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domain of f(x)=sqrt(x^2+3x-4)

domain

f (x) = x^{2} + 3 x - 4

x \leq - 4 or x \geq 1

Interval Notation

(- \infty, - 4] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 1

The function domain

x \leq - 4 or x \geq 1

4 x^{2} + 8

2 - \frac{x}{x - 2}

f (x) = (x - 2)^{2} (x + 1)^{3} (3 x - 8)

x^{2} - 1

f (x) = \frac{1}{x + 1}

What is the domain of f(x)=sqrt(x^2+3x-4) ?
The domain of f(x)=sqrt(x^2+3x-4) is x<=-4\lor x>= 1