What is the critical x^3-9x^2+27x+3 ?

The critical x^3-9x^2+27x+3 is x=3

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critical x^3-9x^2+27x+3

critical points

x^{3} - 9 x^{2} + 27 x + 3

x = 3

Solution steps

x^{3} - 9 x^{2} + 27 x + 3

Find where

f^{'} (x)

is equal to zero or undefined

x = 3

Identify critical points not in

f (x)

domain

Domain of

x^{3} - 9 x^{2} + 27 x + 3 : - \infty < x < \infty

All critical points are in domain

x = 3

f (x) = 2 x^{4} - x^{2}

f (x) = 4 x + 1 - 4

\frac{x + 1}{x ^{2} + 1}

3 x - 4 y = 12

f (x) = \frac{x - 3}{( x + 6 ) ( x - 3 )}