slopeintercept 3x+y-2=0

解答

斜率截距

3 x + y - 2 = 0

y = - 3 x + 2

求解步骤

3 x + y - 2 = 0

转换为斜率-截距形式:

y = - 3 x + 2

对于

y = mx + b

形式的直线方程，斜率为

m

且

y

轴截距为

b

y = - 3 x + 2

s hi f t f (x) = \frac{1}{2} - \frac{1}{2} cos (2 x - \frac{π}{4})

d o main f (x) = \frac{x}{x ^{2} - 3 x + 2}

a sy m pt o t es f (x) = \frac{( 2 x + 4 )}{( x ^{2} - 16 )}

d o main \frac{X ^{2} + 3 X - 4}{X ^{4} - X ^{3} + X ^{2} - X}

m o n o t o n e x - 3 + \frac{2}{x + 1}