定义域 f(x)=sqrt(-(2x)/3+10)

解答

定义域

f (x) = - \frac{2 x}{3} + 10

x \leq 15

间隔符号

(- \infty, 15]

求解步骤

对于根式找到非负值:

x \leq 15

函数定义域

x \leq 15

a sy m pt o t es f (x) = \frac{x + 1}{( x + 3 ) ( x - 2 )}

d o main f (x) = - 7 x^{2}

a sy m pt o t es f (x) = \frac{1}{x ^{2} + 1}

r an g e f (x) = \frac{1}{6} x - 4

f (x) = tan^{2} (x)