What is the critical f(x)=10te^{3-t^2} ?

The critical f(x)=10te^{3-t^2} is t=-1/(sqrt(2)),t= 1/(sqrt(2))

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critical f(x)=10te^{3-t^2}

critical points

f (x) = 10 t e^{3 - t^{2}}

t = - \frac{1}{2}, t = \frac{1}{2}

Solution steps

10 t e^{3 - t^{2}}

Find where

f^{'} (t)

is equal to zero or undefined

t = - \frac{1}{2}, t = \frac{1}{2}

Identify critical points not in

f (t)

domain

Domain of

10 t e^{3 - t^{2}} : - \infty < t < \infty

All critical points are in domain

t = - \frac{1}{2}, t = \frac{1}{2}

f (x) = 3 x + 4

f (x) = (x + 2)^{3} - 6

f (x) = \frac{x + 5}{x ^{3} - 12 x ^{2} + 20 x}

f (x) = \frac{x + 2}{x ^{2} + x - 6}

e^{x - 3} + 3

What is the critical f(x)=10te^{3-t^2} ?
The critical f(x)=10te^{3-t^2} is t=-1/(sqrt(2)),t= 1/(sqrt(2))