What is the critical y=6x^3+8x^2-5x+5 ?

The critical y=6x^3+8x^2-5x+5 is x=-(8+sqrt(154))/(18),x=(-8+sqrt(154))/(18)

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critical y=6x^3+8x^2-5x+5

critical points

y = 6 x^{3} + 8 x^{2} - 5 x + 5

x = - \frac{8 + 154}{18}, x = \frac{- 8 + 154}{18}

Solution steps

6 x^{3} + 8 x^{2} - 5 x + 5

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{8 + 154}{18}, x = \frac{- 8 + 154}{18}

Identify critical points not in

f (x)

domain

Domain of

6 x^{3} + 8 x^{2} - 5 x + 5 : - \infty < x < \infty

All critical points are in domain

x = - \frac{8 + 154}{18}, x = \frac{- 8 + 154}{18}

f (x) = \frac{x}{x ^{2} - ∣ x ∣}

f (x) = \frac{x}{x + 3}

2 x^{3} - 24 x

f (x) = - 7 x + 3

3 x^{\frac{2}{3}} - 2 x

What is the critical y=6x^3+8x^2-5x+5 ?
The critical y=6x^3+8x^2-5x+5 is x=-(8+sqrt(154))/(18),x=(-8+sqrt(154))/(18)