extreme y=x^3-4x^2-3x+8

Lösung

extrempunkte

y = x^{3} - 4 x^{2} - 3 x + 8

Maximum (- \frac{1}{3}, \frac{230}{27}), Minimum (3, - 10)

Schritte zur Lösung

f^{'} (x) = 3 x^{2} - 8 x - 3

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{1}{3},

Absteigend

: - \frac{1}{3} < x < 3,

Ansteigend

: 3 < x < \infty

Stecke

x = - \frac{1}{3}

x^{3} - 4 x^{2} - 3 x + 8 : \frac{230}{27}

Maximum (- \frac{1}{3}, \frac{230}{27})

Stecke

x = 3

x^{3} - 4 x^{2} - 3 x + 8 : - 10

Minimum (3, - 10)

Maximum (- \frac{1}{3}, \frac{230}{27}), Minimum (3, - 10)

d o main ln (t + 5)

s l o p e in t erce pt y - 12 = 4 (x - 6)

in t erce pt s f (x) = y^{2} = x + 25

in t erce pt s f (x) = \frac{x - 4}{x - 2}

d o main f (x) = \frac{9}{x ^{2} + 16} + \frac{1}{x ^{2} - 25}