monotone f(x)=-0.75x^4+15x^3

Lösung

monotone intervalle

f (x) = - 0.75 x^{4} + 15 x^{3}

Ansteigend : - \infty < x < 0, Ansteigend : 0 < x < 15, Absteigend : 15 < x < \infty

Schritte zur Lösung

f^{'} (x) = - 3 x^{3} + 45 x^{2}

Intervalle finden:

Ansteigend

: - \infty < x < 0,

Ansteigend

: 0 < x < 15,

Absteigend

: 15 < x < \infty

Ansteigend : - \infty < x < 0, Ansteigend : 0 < x < 15, Absteigend : 15 < x < \infty

a sy m pt o t es f (x) = \frac{x ^{2} - 1}{x ^{2} + x - 6}

d o main f (x) = arcsin (e^{x^{2} + x - 2})

in f l ec t i o n \frac{x ^{3}}{3} - x^{2} - 3 x

in v erse f (x) = 2 x^{\frac{1}{5}} - 3

a sy m pt o t es \frac{3 x ^{3} - 30 x + 76}{x ^{2} - 10 x + 25}