What is the domain of f(x)=(sqrt(1-x))+(sqrt(36-x^2)) ?

The domain of f(x)=(sqrt(1-x))+(sqrt(36-x^2)) is -6<= x<= 1

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domain of f(x)=(sqrt(1-x))+(sqrt(36-x^2))

domain

f (x) = (1 - x) + (36 - x^{2})

- 6 \leq x \leq 1

Interval Notation

[- 6, 1]

Solution steps

Find non-negative values for radicals:

- 6 \leq x \leq 1

The function domain

- 6 \leq x \leq 1

f (x) = - x + 11

f (x) = - 2 (x + 1)^{2} - 3

y = 4 x - x^{2}

(8) (- 9) m = - \frac{5}{4}

2 x + y = - 1

What is the domain of f(x)=(sqrt(1-x))+(sqrt(36-x^2)) ?
The domain of f(x)=(sqrt(1-x))+(sqrt(36-x^2)) is -6<= x<= 1