What is the shift y=-4cos(2x+pi/3) ?

The shift y=-4cos(2x+pi/3) is Phase:-pi/6 , Vertical:0

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shift y=-4cos(2x+pi/3)

shift

y = - 4 cos (2 x + \frac{π}{3})

Phase : - \frac{π}{6}, Vertical : 0

Solution steps

f (x) = - 4 cos (2 x + \frac{π}{3})

g (B x - C) = cos (2 x + \frac{π}{3}), B = 2, C = - \frac{π}{3}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{- \frac{π}{3}}{2}

- \frac{π}{6}

The vertical shift

D

0

0

f (x) = x^{2} + 2 x - 1

f (x) = \frac{- 4 x - 45}{9 x + 59}

5^{2 x + 1} - 2^{1 - x}

f (x) = 4 + 9 x^{2} - 6 x^{3}

f (x) = ln (x - 5) + 3

What is the shift y=-4cos(2x+pi/3) ?
The shift y=-4cos(2x+pi/3) is Phase:-pi/6 , Vertical:0