What is the domain of g(x)=(sqrt(9+x))/(8-x) ?

The domain of g(x)=(sqrt(9+x))/(8-x) is -9 8

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domain of g(x)=(sqrt(9+x))/(8-x)

domain

g (x) = \frac{9 + x}{8 - x}

- 9 \leq x < 8 or x > 8

Interval Notation

[- 9, 8) \cup (8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 9

Find undefined (singularity) points:

x = 8

Combine real regions and undefined points for final function domain

- 9 \leq x < 8 or x > 8

\frac{x - 7}{3 x - 5}

f (x) = 5 x^{3} - 3 x^{4}

x^{3} - 4 x

y = \frac{6}{5} cos (\frac{2 x}{7})

f (x) = 4 x^{3} - 3 x^{2} - 36 x + 17

What is the domain of g(x)=(sqrt(9+x))/(8-x) ?
The domain of g(x)=(sqrt(9+x))/(8-x) is -9<= x<8\lor x>8