What is the inverse of f(x)=(2x-3)^2 ?

The inverse of f(x)=(2x-3)^2 is (sqrt(x)+3)/2 ,(-sqrt(x)+3)/2

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inverse of f(x)=(2x-3)^2

inverse

f (x) = (2 x - 3)^{2}

\frac{x + 3}{2}, \frac{- x + 3}{2}

Solution steps

y = (2 x - 3)^{2}

Replace

x

with

y

x = (2 y - 3)^{2}

Solve for

y, x = (2 y - 3)^{2}

\frac{x + 3}{2}, \frac{- x + 3}{2}

f (x) = - 4 ln (x) - 1

y = - \frac{12}{7} x - \frac{11}{7}

\frac{3 - x}{2 x - 1}

tan (4 x) d x

f (x) = (\frac{1}{2})^{x}

What is the inverse of f(x)=(2x-3)^2 ?
The inverse of f(x)=(2x-3)^2 is (sqrt(x)+3)/2 ,(-sqrt(x)+3)/2