What is the asymptotes of f(x)=(x^2-6x+9)/(x^3-7x^2) ?

The asymptotes of f(x)=(x^2-6x+9)/(x^3-7x^2) is Vertical: x=0,x=7,Horizontal: y=0

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asymptotes of f(x)=(x^2-6x+9)/(x^3-7x^2)

asymptotes

f (x) = \frac{x ^{2} - 6 x + 9}{x ^{3} - 7 x ^{2}}

Vertical : x = 0, x = 7, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 6 x + 9}{x ^{3} - 7 x ^{2}} : x = 0, x = 7

Horizontal Asymptotes of

\frac{x ^{2} - 6 x + 9}{x ^{3} - 7 x ^{2}} : y = 0

Slant Asymptotes of

\frac{x ^{2} - 6 x + 9}{x ^{3} - 7 x ^{2}} :

None

Vertical : x = 0, x = 7, Horizontal : y = 0

f (x) = \frac{3}{x - 4}

f (x) = 8 x^{5} - 5 x^{4} - 20 x^{3}

x (x + 1) (x - 2)^{2}

f (x) = \frac{( - x + 1 )}{( x - 3 )}

f (x) = \frac{8 x ^{2}}{x ^{4} + 16}

What is the asymptotes of f(x)=(x^2-6x+9)/(x^3-7x^2) ?
The asymptotes of f(x)=(x^2-6x+9)/(x^3-7x^2) is Vertical: x=0,x=7,Horizontal: y=0