What is the critical f(x)=x^3-6x^2+2x ?

The critical f(x)=x^3-6x^2+2x is x=(6-sqrt(30))/3 ,x=(6+sqrt(30))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=x^3-6x^2+2x

critical points

f (x) = x^{3} - 6 x^{2} + 2 x

x = \frac{6 - 30}{3}, x = \frac{6 + 30}{3}

Solution steps

x^{3} - 6 x^{2} + 2 x

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{6 - 30}{3}, x = \frac{6 + 30}{3}

Identify critical points not in

f (x)

domain

Domain of

x^{3} - 6 x^{2} + 2 x : - \infty < x < \infty

All critical points are in domain

x = \frac{6 - 30}{3}, x = \frac{6 + 30}{3}

f (x) = 10 x - 3

f (x) = \frac{x}{3 + x}

(x - 3)^{2} + 1

7 lo g_{10} (1 + 9 x)

(- 6, 5), (0, 2)

What is the critical f(x)=x^3-6x^2+2x ?
The critical f(x)=x^3-6x^2+2x is x=(6-sqrt(30))/3 ,x=(6+sqrt(30))/3