What is the domain of 1/(x^2-x-2) ?

The domain of 1/(x^2-x-2) is x 2

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domain of 1/(x^2-x-2)

domain

\frac{1}{x ^{2} - x - 2}

x < - 1 or - 1 < x < 2 or x > 2

Interval Notation

(- \infty, - 1) \cup (- 1, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 1

The function domain

x < - 1 or - 1 < x < 2 or x > 2

f (x) = \frac{1}{( x ^{2} + 1 )}

f (x) = \frac{( x + 3 )}{( x - 4 )}

f (x) = \frac{x - 2}{x - 3}

f (x) = \frac{3 x - 4}{- 2 x + 7}

\frac{x ^{2}}{64} - \frac{y ^{2}}{36} = 1

What is the domain of 1/(x^2-x-2) ?
The domain of 1/(x^2-x-2) is x<-1\lor-1<x<2\lor x>2