What is the domain of f(x)=\sqrt[6]{x^2-8x-9} ?

The domain of f(x)=\sqrt[6]{x^2-8x-9} is x = 9

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domain of f(x)=\sqrt[6]{x^2-8x-9}

domain

x \leq - 1 or x \geq 9

Interval Notation

(- \infty, - 1] \cup [9, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 9

The function domain

x \leq - 1 or x \geq 9

(3, 0), (- 2, - 5)

f (x) = \frac{2 x ^{3} - 8 x}{x ^{3} + 2 x ^{2}}

f (x) = \frac{4 x - 8}{x + 3}

2 + 3 + 4 x

y = \frac{2}{3} x - 5

What is the domain of f(x)=\sqrt[6]{x^2-8x-9} ?
The domain of f(x)=\sqrt[6]{x^2-8x-9} is x<=-1\lor x>= 9