What is the inverse of f(x)=2x^2-2 ?

The inverse of f(x)=2x^2-2 is sqrt((x+2)/2),-sqrt((x+2)/2)

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inverse of f(x)=2x^2-2

inverse

f (x) = 2 x^{2} - 2

\frac{x + 2}{2}, - \frac{x + 2}{2}

Solution steps

y = 2 x^{2} - 2

Replace

x

with

y

x = 2 y^{2} - 2

Solve for

y, x = 2 y^{2} - 2

\frac{x + 2}{2}, - \frac{x + 2}{2}

x^{3} + 16

- 3 y - x = x + 8

\frac{x ^{2}}{x ^{2} - 4}

(6, - 3), (7, - 2)

f (x) = \frac{5 - 4 x - x ^{2}}{x + 3}

What is the inverse of f(x)=2x^2-2 ?
The inverse of f(x)=2x^2-2 is sqrt((x+2)/2),-sqrt((x+2)/2)