What is the domain of f(x)=(2x-1)/(2x^4+x^3-6x^2) ?

The domain of f(x)=(2x-1)/(2x^4+x^3-6x^2) is x 3/2

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domain of f(x)=(2x-1)/(2x^4+x^3-6x^2)

domain

f (x) = \frac{2 x - 1}{2 x ^{4} + x ^{3} - 6 x ^{2}}

x < - 2 or - 2 < x < 0 or 0 < x < \frac{3}{2} or x > \frac{3}{2}

Interval Notation

(- \infty, - 2) \cup (- 2, 0) \cup (0, \frac{3}{2}) \cup (\frac{3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = \frac{3}{2}, x = - 2

The function domain

x < - 2 or - 2 < x < 0 or 0 < x < \frac{3}{2} or x > \frac{3}{2}

f (x) = \frac{- x ^{2} - 4 x + 5}{4 x - 4}

f (x) = \frac{x}{3 x - 4}

\frac{y}{y - 6} + \frac{15}{y + 6}

f (x) = 2 x^{2} - 3

y = - 2 x^{2} + 4 x + 7

What is the domain of f(x)=(2x-1)/(2x^4+x^3-6x^2) ?
The domain of f(x)=(2x-1)/(2x^4+x^3-6x^2) is x<-2\lor-2<x<0\lor 0<x< 3/2 \lor x> 3/2