What is the critical f(x)=x^2e^{(18x)} ?

The critical f(x)=x^2e^{(18x)} is x=-1/9 ,x=0

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critical f(x)=x^2e^{(18x)}

critical points

f (x) = x^{2} e^{(18 x)}

x = - \frac{1}{9}, x = 0

Solution steps

x^{2} e^{18 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{9}, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{2} e^{18 x} : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{9}, x = 0

f (x) = - x - 1 - 3

(2, 3), (12, - 15)

f (x) = \frac{4}{x ^{2} + 8}

f (x) = \frac{2}{7 - x}

f (x) = - 2^{x} + 100

What is the critical f(x)=x^2e^{(18x)} ?
The critical f(x)=x^2e^{(18x)} is x=-1/9 ,x=0