What is the inflection f(x)=4x^3-6x^2+7x-7 ?

The inflection f(x)=4x^3-6x^2+7x-7 is (1/2 ,-9/2)

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inflection f(x)=4x^3-6x^2+7x-7

inflection points

f (x) = 4 x^{3} - 6 x^{2} + 7 x - 7

(\frac{1}{2}, - \frac{9}{2})

Solution steps

f^{''} (x) = 24 x - 12

Find intervals:

Concave Downward

: - \infty < x < \frac{1}{2},

Concave Upward

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

4 x^{3} - 6 x^{2} + 7 x - 7 : - \frac{9}{2}

(\frac{1}{2}, - \frac{9}{2})

- x^{3} + 3 x^{2} + 10 x

x^{\frac{1}{7}} (x + 8)

f (x) = 4 x^{2}

f (x) = e^{c o s (x)}

g (x) = \frac{x}{2}

What is the inflection f(x)=4x^3-6x^2+7x-7 ?
The inflection f(x)=4x^3-6x^2+7x-7 is (1/2 ,-9/2)