What is the perpendicular y=2x+3,(1,3) ?

The perpendicular y=2x+3,(1,3) is y=-1/2 x+7/2

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perpendicular y=2x+3,(1,3)

perpendicular

y = 2 x + 3, (1, 3)

y = - \frac{1}{2} x + \frac{7}{2}

Solution steps

Find the line

y = mx + b

perpendicular to

y = 2 x + 3

that passes through

(1, 3)

Find the slope of

y = 2 x + 3 : m = 2

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(1, 3) : y = - \frac{1}{2} x + \frac{7}{2}

y = - \frac{1}{2} x + \frac{7}{2}

f (x) = \frac{8}{( 2 x - 5 ) ^{3}}

f (x) = \frac{x ^{2} + 8 x - 4}{- 2 x - 4}

a

f (x) = \frac{x}{x ^{2} - 1}

x - 5 + 3

What is the perpendicular y=2x+3,(1,3) ?
The perpendicular y=2x+3,(1,3) is y=-1/2 x+7/2