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Popular >

range of x^2+x+2

Solution

range

x^{2} + x + 2

Solution

f (x) \geq \frac{7}{4}

+1

Interval Notation

[\frac{7}{4}, \infty)

Solution steps

Vertex of

x^{2} + x + 2 :

Minimum

(- \frac{1}{2}, \frac{7}{4})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- \frac{1}{2}, \frac{7}{4})

f (x) \geq \frac{7}{4}

Popular Examples

range of f(x)=sqrt(6x)range

f (x) = 6 x

intercepts of y=-2 intercepts

y = - 2

domain of f(x)=((1-5x))/2 domain

f (x) = \frac{( 1 - 5 x )}{2}

inverse of f(x)=(x-5)/x inverse

f (x) = \frac{x - 5}{x}

asymptotes of f(x)=((3x^3-3))/(x-x^2)asymptotes

f (x) = \frac{( 3 x ^{3} - 3 )}{x - x ^{2}}

Frequently Asked Questions (FAQ)

What is the range of x^2+x+2 ?
The range of x^2+x+2 is f(x)>= 7/4