What is the monotone f(x)= 1/(x^2-6x+12) ?

The monotone f(x)= 1/(x^2-6x+12) is Increasing:-infinity <x<3,Decreasing:3<x<infinity

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monotone f(x)= 1/(x^2-6x+12)

monotone intervals

f (x) = \frac{1}{x ^{2} - 6 x + 12}

Increasing : - \infty < x < 3, Decreasing : 3 < x < \infty

Solution steps

f^{'} (x) = - \frac{2 x - 6}{( x ^{2} - 6 x + 12 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 3,

Decreasing

: 3 < x < \infty

Increasing : - \infty < x < 3, Decreasing : 3 < x < \infty

f (x) = x^{2} + 5 x

(x - 2)^{(4)}

f (x) = 4 x^{3} + 5 x^{2}

f (x) = e^{x} - x^{2} - 2 x + 6

f (x) = - 3 \cdot 5^{- x + 3}

What is the monotone f(x)= 1/(x^2-6x+12) ?
The monotone f(x)= 1/(x^2-6x+12) is Increasing:-infinity <x<3,Decreasing:3<x<infinity