What is the inverse of f(x)=sqrt(3-2x)+8 ?

The inverse of f(x)=sqrt(3-2x)+8 is -(x^2-16x+61)/2

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inverse of f(x)=sqrt(3-2x)+8

inverse

f (x) = 3 - 2 x + 8

- \frac{x ^{2} - 16 x + 61}{2}

Solution steps

y = 3 - 2 x + 8

Replace

x

with

y

x = 3 - 2 y + 8

Solve for

y, x = 3 - 2 y + 8

- \frac{x ^{2} - 16 x + 61}{2}

f (x) = x^{4} - 32 x^{2} + 9

f (x) = sin (\frac{2 π}{3}) x

f (x) = \frac{5 x + 7}{x}

3 cos (2 x + π)

What is the inverse of f(x)=sqrt(3-2x)+8 ?
The inverse of f(x)=sqrt(3-2x)+8 is -(x^2-16x+61)/2