What is the inverse of h(x)=\sqrt[3]{x-2}+3 ?

The inverse of h(x)=\sqrt[3]{x-2}+3 is x^3-9x^2+27x-25

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inverse of h(x)=\sqrt[3]{x-2}+3

inverse

x^{3} - 9 x^{2} + 27 x - 25

Solution steps

Replace

x

with

y

Solve for

x^{3} - 9 x^{2} + 27 x - 25

f (x) = \frac{x + 2}{x}

f (x) = arctan (ln (e^{t a n (x^{2})}))

y = \frac{1}{2} x - 4

f (x) = 13 x^{4} - 78 x^{2}

cos (x)

What is the inverse of h(x)=\sqrt[3]{x-2}+3 ?
The inverse of h(x)=\sqrt[3]{x-2}+3 is x^3-9x^2+27x-25