What is the inverse of f(x)= 1/3 x^3-4 ?

The inverse of f(x)= 1/3 x^3-4 is cube root of 3x+12

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inverse of f(x)= 1/3 x^3-4

inverse

f (x) = \frac{1}{3} x^{3} - 4

Solution steps

y = \frac{1}{3} x^{3} - 4

Replace

x

with

y

x = \frac{1}{3} y^{3} - 4

Solve for

y, x = \frac{1}{3} y^{3} - 4

cos (x) - 3

1 - x - x^{2}

f (x) = \frac{( 5 x - 2 )}{- 5 x + 1}

(3, - 2), (13, 10)

y = 3 x - 2, (- 1, 3)

What is the inverse of f(x)= 1/3 x^3-4 ?
The inverse of f(x)= 1/3 x^3-4 is cube root of 3x+12