What is the inverse of f(x)=2sqrt(x-5)+1 ?

The inverse of f(x)=2sqrt(x-5)+1 is (x^2+1)/4-x/2+5

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inverse of f(x)=2sqrt(x-5)+1

inverse

f (x) = 2 x - 5 + 1

\frac{x ^{2} + 1}{4} - \frac{x}{2} + 5

Solution steps

y = 2 x - 5 + 1

Replace

x

with

y

x = 2 y - 5 + 1

Solve for

y, x = 2 y - 5 + 1

\frac{x ^{2} + 1}{4} - \frac{x}{2} + 5

f (x) = - 2 x^{2} - 2

(8 q, 8 q), (2 q, 3 q)

f (x) = 3 (\frac{1}{4})^{x + 5}

(4, - 63.5), (20, 63.5)

y = - 2 x - 4

What is the inverse of f(x)=2sqrt(x-5)+1 ?
The inverse of f(x)=2sqrt(x-5)+1 is (x^2+1)/4-x/2+5