What is the intercepts of f(x)=(x+4)^2+1 ?

The intercepts of f(x)=(x+4)^2+1 is Y Intercepts: (0,17)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

intercepts of f(x)=(x+4)^2+1

intercepts

f (x) = (x + 4)^{2} + 1

Y Intercepts : (0, 17)

Solution steps

x -

axis interception points of

(x + 4)^{2} + 1 :

None

y -

axis interception point of

(x + 4)^{2} + 1 : (0, 17)

Y Intercepts : (0, 17)

f (8) = 1 f (10) = - 2

(8, 7), (10, 16)

f (x) = 6 x^{2} + 2

x^{3} - 3 x^{2} - 45 x + 5

f (x) = \frac{x - 6}{10}

What is the intercepts of f(x)=(x+4)^2+1 ?
The intercepts of f(x)=(x+4)^2+1 is Y Intercepts: (0,17)