What is the domain of f(x)= 1/(x(x+2)) ?

The domain of f(x)= 1/(x(x+2)) is x 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 1/(x(x+2))

domain

f (x) = \frac{1}{x ( x + 2 )}

x < - 2 or - 2 < x < 0 or x > 0

Interval Notation

(- \infty, - 2) \cup (- 2, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 2

The function domain

x < - 2 or - 2 < x < 0 or x > 0

y = \frac{1}{x ^{2} - 9}

\frac{9}{x - 4}

f (x) = \frac{x ^{2} - 4 x - 21}{3 x - 21}

y = \frac{x ^{2} - 16}{9 - x ^{2}}

f (x) = \frac{1}{1 - e ^{x}}

What is the domain of f(x)= 1/(x(x+2)) ?
The domain of f(x)= 1/(x(x+2)) is x<-2\lor-2<x<0\lor x>0